Jujitsu Time

First off we went through simple harmonic motion and the simpleness of deriving it's formula.
Now All Questions are supposed to be answered. How does this relate to the pendulum?


@= Theta for the purposes of this

Also on Centripetal Motion:
4π^2r/T^2=a=v^2/R

We can Determine that 2π*Square Root of (L/G) = 2π*Square root of (M/K) = T.

We use the following

Determining Simple Harmonic Motion over a Pendulum
Things we can assume:
Ay=O (Basically it's not moving up and down.)
Cos@ =1 (There is minimal movement of the pendulum so the cosine of the degrees is very close to 1 because the degrees movement is really small).

The Jujitsu Way to Own a Simple Pendulum problem in the face.
Step 1, Brick Breaker Create a Free Body Diagram
Step 2, Follow-Up Punch Find the net force (add up all your forces (using cosine
Step 3, See the Shadows: Find the Net force Fnet=<-Ft sin@, Ft cos@ - mg>
Step 4, Headbutt: Fnet= ma a=

Interlude, Break Period: Sin@=X/L

Step 5, Sweep the leg: Analayze Components y FtCos@ -mg = m*ay
Ft-mg=0
FT=mg
Step 6, Sweep the other leg: X:=-Fsin@=ma of x
Step 7, Wax on: Insert sin@ = X/L, -Ft x/l =MAX
Step 8, Wax off: Insert Ft=Mg
(-mgx)/L= MaX

Gather your thoughts: -Mg/L*x=Max
M's cancel out in the equation above ^.
-g/L x = ax

Step 9, Go for the crane kick: Look at the Force
-mg/L*x = max
Constant (k) = -MG/L
Linear Resting Force F=-Kxo
T=2π*Square Root of (M/K)
T= 2π*Square Root of (M/Mg/L)
T= 2π*Square Root of (L/G)

Homework is to do the hardest problem ever AND make sure you turn in Homework 4H. Next Scribe is whomever. Volunteer in class on Friday.... jk it's Sana.